Question 1084174
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<pre>
The only solution in the interval [{{{0}}},{{{2pi}}}) are x= 0 ans x= {{{pi}}}.


The solutions on the number line are x = {{{k*pi}}}, k = 0, +/-1, +/-2, . . . 



<U>The steps</U>:


{{{tan(x)*sin^2(x)}}} = {{{1.21*tan(x)}}}  ====>

{{{tan(x)*sin^2(x) - 1.21*tan(x)}}} = 0  ====>

{{{tan(x)*(sin^2(x) - 1.21)}}} = 0.


The term (sin^2(x) - 1.21) is NEVER zero.


Therefore, the only solutions come from tan(x) = 0.
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Solved.