Question 95787
L1; m = {{{(y2-y1)/(x2-x1)}}}
 m = {{{(3-1)/(0 - (-2))}}}
m = {{{2/2}}}
L2; m = {{{0-2)/(5-3)}}}
 m = {{{-2/2}}}
Yes they are perpendicular, lines are perpendicular if there slopes are negative reciprocals.
:)