Question 95850
THE DIAGONAL OF A SQUARE=8 
THUS YOU HAVE A RIGHT TRIANGLE WITH 2 EQUAL SIDES & A HYPOTENUSE OF 8
X^2+X^2=8^2
2X^2=64
X^2=32
X=SQRT32
X=5.658542 CM. LENGTH OF THE SIDES.
PROOF
5.658542^2+5.658542^2=8*2
32+32=64
64=64