Question 1084021
If 3+log10x =2log 10y then x =?
Assume the problem is
{{{3+log((10x)) = 2log((10y))}}}
{{{log((10x)) = 2log((10y))-3}}}
the exponent equiv
{{{log((10x)) = log((10y)^2)-3)}}}
{{{log((10x)) = log((100y^2))-3)}}}
Subtracting 3 from a log is the same as dividing by 1000, can be written as 
{{{log((10x)) = log(((100y^2)/1000)))}}}
Cancel
{{{log((10x)) = log(((y^2)/10)))}}} 
therefore
10x = {{{y^2/10}}} 
x = {{{y^2/100}}}