Question 95759
The perimeter of a rectangle is 3 more than three times its width. Find the length and width of the rectangle.
:
The  relationship between the width and the length is not given, therefore,
there are an unlimited number solutions to this problem:
:
x = width, let y = the length
:
It says,"perimeter of a rectangle is 3 more than three times its width." therefore
P = 3x + 3
:
2L + 2W = P
Therefore:
2y + 2x =  3x + 3
2y = 3x + 3 - 2x
2y = x + 3
y = {{{((x+3))/2}}}
:
Substituting any value for x (width), gives a value for y(length) that will
satisfy this problem;
:
For example try x = 5: 
y = {{{(5+3)/2}}}
y = 4
:
2(4) + 2(5) = 18
:
Given that 3x + 3 = P
3(5) + 3 = 18 
:
A few other length/width values:
 x | y
-------
 1 | 2
 2 | 2.5
 3 | 3
 4 | 3.5
:
Did this help you?