Question 1083943
How can I solve (x+3)(x+4)=0 and 2x(x-3)=15????
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(x+3)(x+4)=0
If the product = 0, either
x+3 = 0 --> x = -3
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or x+4 = 0 --> x = -4
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2x(x-3)=15
2x^2 - 6x - 15 = 0
*[invoke solve_quadratic_equation 2,-6,-15]