Question 1083888
his room is 3.5 meters wide, 3.9 meters long, and 2.5 meters high.


there are 2 side walls that each measure 3.5 wide by 2.5 high.


each of these side walls has an area of 3.5 * 2.5 = 8.75 square meters.


the total area for both side walls is therefore 2 * 8.75 = 17.5 square meters.


there are the front and back wall that each measure 3.9 long by 2.5 high.


each of these front and back walls has an area of 3.9 * 2.5 = 9.75 square meters.


the total area for the front and back walls is therefore 2 * 9.75 = 19.5 square meters.


there is the ceiling that measures 3.9 long by 3.5 wide.


the total area for the ceiling is 3.9 * 3.5 = 13.65 square meters.


the total square meters that would need to be painted, had there been no door or window that would not be painted, is therefore 17.5 + 19.5 + 13.65 = 50.65 square meters.


the door is 2 meters high by 85 centimeters long.


the window is 60 centimeters high by 40 centimeters long.


you would want to convert centimeters to meters so all units of measure are the same.


1 meter is equal to 100 centimeters.


that means you have to divide centimeters by 100 to get meters.


the door measures 2 meters high by 85 centimeters wide.


convert everything to meters and the door measures 2 meters high by .85 meters long.


the area of the door is 2 * .85 = 1.7 square meters.


the window is 65 centimeters high by 40 centimeters long.


convert that to meters and the window measures .65 meters high by .4 meters long.


the area of the window is .65 * .4 = .26 square meters.


the total area of the door and the window is 1.7 + .26 = 1.96 square meters.


since the door and the window won't be painted, the total surface area of the room that will be painted is 50.65 - 1.96 = 48.69 square meters.


the walls and the ceiling will be painted but the door and the window will not.