Question 1083871
6y^2-y-51 turns into y^2-y-306
Factor that into (y-18)(y+17), then divide the constant by 6 and reduce fully to (y-3)(y+17/6)
the factors then are (y-3) and (6y+17)
A=2
B=17
C=3
(AC)^2=36
36-17=19 is the answer.