Question 1083838
(1/6) probability will get a 1 and run 2 miles, 50 days out of 300, 100 days out of 600.
(1/2) probability get 2,3,4 and run 3 miles, 150 days out of 300, 300 days out of 600.
(1/3) probability get a 5,6 and run 4 miles, 100 days out of 300, 200 days out of 600.
In 300 days would run 100+450+400=950 miles or 3.17 miles a day.
In 600 days would run 200+900+800=1900 miles or 3.17 miles a day.
That is the expected value
(1/6)(2)+(1/2)*3+(1/3)*4=(1/3)+(3/2)+(4/3)=(38/12)=3.17 (3 1/6)