<PRE><B>Question 1083792</B>
For what value of k the line 2x-y+k=0 is tangent to the parabola y^2=6x?
--------
2y*dy = 6*dx
dy/dx = 3/y = the slope of the parabola
----
The slope of 2x-y+k=0 is 2
---
3/y = 2
y = 3/2;  x = 3/8
The tangent point is (3/8,3/2)
--------
2x-y+k=0
3/4 - 3/2 + k = 0
k = 3/4

</PRE>