Question 1083786
Dimensions w+2 and w;
Diagonal, 10;


{{{(w+2)^2+w^2=10^2}}}
-

{{{w^2+4w+4+w^2=100}}}
{{{2w^2+4w+4-100=0}}}
{{{w^2+2w+2-50=0}}}
{{{w^2+2w-48=0}}}
{{{(w-6)(w+8)=0}}}


{{{w=6}}}, and length: {{{w+2=8}}}.


AREA:
{{{w(w+2)}}}={{{48}}}