<PRE><B>Question 1083771</B>
The hypotenuse of a right triangle is twice as long as one of the legs. If the other leg is the square root of 8, find the other leg. So I thought the problem would be set up as x^2 + square root of eight squared = 2x squared. but the answer after I work the problem is not correct.
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1 side = sqrt(8)
Other side = a
c = 2a
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c^2 = a^2 + 8
(2a)^2 = a^2 + 8
4a^2 = a^2 + 8
3a^2 = 8
a^2 = 8/3
{{{a = sqrt(8/3) = 2sqrt(6)/3}}}
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