Question 1083599
if you have this:

{{{y= 1/(x + 6)-6}}} 

than vertical a asymptote is the value of {{{x}}} that makes denominator equal to zero:

so, if {{{x+6=0}}}->{{{x=-6}}} and that is vertical a asymptote 

{{{drawing( 600, 600, -15, 10, -10, 10, 
line(-6,-10,-6,10),
 graph( 600, 600, -15, 10, -10, 10,  1/(x + 6)-6)) }}}