Question 1083426
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sum of four consecutive numbers is 62
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{{{n+n+1+n+2+n+3=62}}}
{{{4n+6=62}}}
{{{4n=56}}}
{{{n=14}}}


The FOUR consecutive numbers are 14, 15, 16, 17.



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Find the product between the last two and the first two
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{{{(14)(15)(16)(17)=21420}}}