Question 1083280
given:
{{{d[1]=2d[2]}}}
{{{a=19in}}}

{{{19^2=(d[1]/2)^2+(d[2]/2)^2}}}

{{{361=(2d[2]/2)^2+(d[2]/2)^2}}}

{{{361=(d[2])^2+(d[2])^2/4}}}

{{{361=(5/4)(d[2])^2}}}

{{{361/(5/4)=(d[2])^2}}}

{{{288.8=(d[2])^2}}}

{{{d[2]=sqrt(288.8)}}}

{{{d[2]=16.99in}}}