Question 1083256


given:
{{{d[1]=2d[2]}}}
{{{a=16in}}}

{{{16^2=(d[1]/2)^2+(d[2]/2)^2}}}

{{{256=(2d[2]/2)^2+(d[2]/2)^2

{{{256=(d[2])^2+(d[2])^2/4}}}

{{{256=(5/4)(d[2])^2}}}

{{{256/(5/4)=(d[2])^2}}}

{{{204.8=(d[2])^2}}}

{{{d[2]=sqrt(204.8)}}}

{{{d[2]=14.31}}}


answer: c. {{{14.31in}}}