Question 1083257

given:

{{{d[1]=2d[2]}}} where {{{d[2]}}} is shorter diagonal

{{{a=12in}}}

side, and half of each diagonal form right triangle, so use Pythagorean theorem

{{{12^2=(d[1]/2)^2+(d[2]/2)^2}}}

{{{144=(2d[2]/2)^2+(d[2]/2)^2}}}

{{{144=(d[2])^2+(d[2])^2/4}}}

{{{144=(5/4)(d[2])^2}}}

{{{144/(5/4)=(d[2])^2}}}

{{{115.2=(d[2])^2}}}

{{{d[2]=sqrt(115.2)}}}

{{{d[2]=10.73}}}

answer is: b. {{{10.73in}}}