Question 1083153
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For the radius of the circumscribed circle use the formula 


R = {{{abc/4S}}},


where a, b and c are the sides measures and S is the area of the triangle.


(See the lesson  <A HREF=http://www.algebra.com/algebra/homework/Surface-area/Proof-of-the-formula-for-the-radius-of-the-circumscribed-circle.lesson>Proof of the formula for the radius of the circumscribed circle</A>  in this site).



For the radius of the inscribed circle use the formula 


r = {{{S/p}}},


where a, b and c are the sides measures and p is the semi-perimeter of the triangle.


(See the lesson  <A HREF=http://www.algebra.com/algebra/homework/Surface-area/Proof-of-the-formula-for-the-area-of-a-triangle-via-the-radius-of-the-inscribed-circle.lesson>Proof of the formula for the area of a triangle via the radius of the inscribed circle</A> &nbsp;and   in this site).


To find the area of the given triangle, find its altitude drawn to the base first:

h = {{{sqrt(b^2 - (a/2)^2)}}} = {{{sqrt(20^2 - 12^2)}}} = {{{sqrt(400-144)}}} = {{{sqrt(256)}}} = 16 cm.


Then the area of the triangle is S = {{{(1/2)*a*h}}} = {{{(1/2)*24*16}}} = 192 cm^2.
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From this point, complete the solution on your own.


Also, &nbsp;you have this free of charge online textbook on Geometry

&nbsp;&nbsp;&nbsp;&nbsp;<A HREF=https://www.algebra.com/algebra/homework/Triangles/GEOMETRY-your-online-textbook.lesson>GEOMETRY - YOUR ONLINE TEXTBOOK</A> 

in this site.


The referred lessons are the part if this textbook under the topic "<U>Area of triangles</U>".