Question 1083054
It is a 2-tailed test.
Reject Ho if |z|>2.33.  The absolute value of z is a nice shortcut to say if z is <-2.33 or >+2.33 one will reject Ho.
z=1.51
p-value is 0.1326.
With a calculator, that comes up.  Without, one looks up the z-value for 1.51 in a table and that is one sided probability.  For two sided probability, multiply the z-value by 2.