Question 1082999
<pre>
The random variable X has the following distribution.

 X         p(X)
---------------
-1         3c
 0         2c
 1         0.4
 2         0.1

Find the value of constant c.
<font face="lucida console" size=4><b>
The sum of the probabilities must = 1, so the equation is

3c + 2c + 0.4 + 0.1 = 1
           5c + 0.5 = 1
                 5c = 0.5
                  c = 0.1

That's the answer.  That means the distribution is

 X         p(X)
---------------
-1         0.3
 0         0.2
 1         0.4
 2         0.1
---------------
     sum = 1.0

Edwin</pre></font></b>