Question 1082884
Given: f(x)=8-5x 
A. Find f(-2)

f(x)=8-5x
<pre><b>
Everywhere there is an x, substitute (-2) instead:

f(-2) = 8-5(-2)

Simplify

f(-2) = 8+10

f(-2) = 18
</pre>
B. Find x, when f(x)=8
<pre>
f(x)=8-5x

Everywhere there is an f(x), substitute 8 instead:

8=8-5x

Solve for x

Subtract 8 from both sides

0=-5x

Divide both sides by -5

{{{0/(-5)=(-5x)/(-5)}}}

{{{0=(cross(-5)x)/cross(-5)}}}

{{{0=x}}}
</pre>
C. State the domain and range of the function
<pre>
Since there are no denominators or square roots,
or special functions, such as absolute values, the domain 
is always {{{(matrix(1,3,-infinity,",",infinity))}}} 

Since the largest power of x is an odd number, the range is
{{{(matrix(1,3,-infinity,",",infinity))}}}.

Edwin</pre>