Question 1082791
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a)  The rocket is at the top of the building the instant it is launched, that is when *[tex \Large t\ =\ 0].  So what is the value of *[tex \Large f(0)]?


b)  The height of the ground is zero, so what is the positive value of *[tex \Large t] that makes *[tex \Large f(t)\ =\ 0]?


c)  Since the rocket starts out higher than 25 meters, the rocket will be at 25 meters at the positive value of *[tex \Large t] that makes *[tex \Large f(t)\ =\ 25]


Hint: for b) and c) you will get both positive and negative values of *[tex \Large t].  But since the rocket is launched at *[tex \Large t\ =\ 0], any negative value of *[tex \Large t] would represent time BEFORE the rocket was launched -- information that is of no use.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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