Question 1082670
There are {{{ 3*4 = 12 }}} face cards which are
J, Q, and K of the 4 suits
Then, avoiding counting twice, Ace through ten
of diamonds, {{{ 10 }}} cards
{{{ 12 + 10 = 22 }}}
{{{ 22/52 = 11/26 }}}
The probabiity is 11/26