Question 1082504
log base 4 of X - log base 16 of (x+3) = 1/2


{{{log(4,x)-log(16,(x+3))=1/2}}}


{{{log(4,x)-(log(4,(x+3))/log(4,16))=1/2}}}, using Change of Base formula


{{{log(4,x)-(log(4,(x+3))/log(4,(4^2)))=1/2}}}


{{{log(4,x)-(log(4,(x+3))/(2*log(4,4)))=1/2}}}


{{{log(4,x)-(log(4,(x+3))/2)=1/2}}}


{{{2log(4,x)-log(4,(x+3))=1}}}


{{{log(4,x^2)-log(4,(x+3))=1}}}


{{{log(4,((x^2)/(x+3)))=1}}}


Next, put into exponential form,... and solve for x.