Question 1082319
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You are given the measure of a side of the base, <i>b</i>, and the slant height, <i>s</i>.  In order to calculate the volume, you need the apothem, <i>a</i>, of the base which is the measure of the distance from the center of the base to the midpoint of one side.  For a regular hexagon, the apothem is the height of an equilateral triangle with sides congruent to a side of the hexagon.  I leave the calculation of this value as an exercise for the student.  And then you need the height, <i>h</i>, which is the measure from the center of the base to the apex.  Use Pythagoras:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h\ =\ \sqrt{s^2\ -\ a^2}]


Then the volume of your pyramid is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ V\ =\ abh]


For the surface area, you need to decide whether you want the Lateral Surface Area (just the sides excluding the area of the base) or the Total Surface Area (sides AND the base):


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ SA_L\ =\ 3bs]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ SA_T\ =\ 3ab\ +\ SA_L]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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