Question 1082450
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None of the answers are possible.  The sum of all of the occurrences must, perforce, equal 2,000 and the smallest sum for any of the four given answers is, just by cursory examination, in the neighborhood of 3000.


Secondly, if the chance of 3, 6, 7, and 8 are EACH 22%, then the probability of 3 or 6 or 7 or 8 is 88%, and the probability of any of the other numbers is, in the aggregate, 12%, or individually 2.4%.  That means 3, 6, 7, or 9 are each roughly 9 times more likely than any of the others individually.


I would expect a distribution that was closer to:


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   1     2     3     4     5     6     7     8     9
  48    48   440    48    48   440   440   440    48
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Which doesn't even come close to any of your given answers


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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