Question 1082426
{{{ cos( csc^(-1)( 17/15 ) ) }}}
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This is saying:
" What is the cosine of the angle whose cosecant
is {{{ 17/15 }}} ?
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The csc = 1/sin , so If {{{ csc (theta ) = 17/15 }}},
then {{{ sin( theta ) = 15/17 }}}
Find the other side of this triangle
{{{ a^2 + 15^2 = 17^2 }}}
{{{ a^2 = 289 - 225 }}}
{{{ a^2 = 64 }}}
{{{ a = 8 }}}
So, {{{ cos(theta) = 8/17 }}} and
{{{ cos( csc^(-1)( 17/15 )) = 8/17 }}}
Hope this helps