Question 1082391
{{{A=int((x-2)(x+2),dx,x=3,0)}}}
{{{A=int((x^2-4),dx,x=3,0)}}}
{{{A=x^3/3-4x+C}}}
{{{A=0^3/3-4(0)-(3^3/3-4(3))}}}
{{{A=-(9-12)}}}
{{{A=3}}}