Question 1082332
Here is a start.


Pieces are lengths x and y.
{{{x+y=12}}}


Take the x length and make into a square.
Each side becomes {{{x/4}}} and area for this is  {{{(1/16)x^2}}}.



Take the y length to make the circle. Let r be radius.
{{{y=2pi*r}}}
and area is  {{{pi*r^2}}}

{{{pi(y/(2pi))^2}}}

{{{(1/(4pi))y^2}}}


{{{(1/(4pi))(12-x)^2}}}



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The sum of the areas is  {{{highlight_green((1/16)x^2+(1/(4pi))(12-x)^2)}}};  now can you continue and then finish?