Question 1082283
The events "get a home run" and "strikeout" are mutually exclusive events. If one event happens, then the other cannot happen. 


Because the events are mutually exclusive, this allows us to simply add the corresponding probabilities for getting a home run (8%) and striking out (40%)


Keep in mind that 
8% = 8/100 = 0.08
40% = 40/100 = 0.40


P(home run OR striking out) = P(home run) + P(striking out)
P(home run OR striking out) = 0.08 + 0.40
P(home run OR striking out) = 0.48
P(home run OR striking out) = <font color=red>48%</font>


Answer: <font color=red>Choice A) 48%</font>