Question 1082223
Convert to the focus form of the parabola.
{{{4y=x^2-12x+72}}}
{{{4y=(x^2-12x+36)+72-36}}}
{{{4y=(x-6)^2+36}}}
{{{4y-36=(x-6)^2}}}
{{{4(y-9)=(x-6)^2}}}
So the vertex is ({{{6}}},{{{9}}}) and the focus is ({{{6}}},{{{9+1}}})=({{{6}}},{{{10}}}).
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*[illustration gg14.JPG].