Question 1082030
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4a^2\ -\ 10ab\ -\ 6b^2\ =\ 20]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4a^2\ -\ 12ab\ +\ 2ab\ -\ 6b^2\ =\ 20]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4a(a\ -\ 3b)\ +\ 2b(a\ -\ 3b)\ =\ 20]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (4a\ +\ 2b)(a\ -\ 3b)\ =\ 20]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ -\ 3b\ =\ \frac{20}{4a\ +\ 2b}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3a\ -\ 9b\ =\ \frac{60}{4a\ +\ 2b}\ =\ \frac{30}{2a\ +\ b}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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