Question 1082046
{{{log(19,(10-2a))=log(19,(-3a-6))}}}


Same base; the inputs to the logs on both sides are equal.
{{{10-2a=-3a-6}}}
{{{-2a+3a=-6-10}}}
{{{highlight(a=-16)}}}


Are the logs of the original expressions those of positive number inputs, or non-negative inputs?


{{{10-2(-16)=10+32=42}}}
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{{{-3(-16)-6=48-6=42}}}
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Solution works.