Question 1082047
.
solve the logarithmic equation:
 log[subscript 16] (3-5n)= log [subscript 16] (2n+7)
I got no solution 
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<pre>
{{{log(16,(3-5n))}}} = {{{log(16,(2n+7))}}}  ====>

3 - 5n = 2n + 7  ====>

3 - 7 = 2n + 5n

-4 = 7n

====>  n = {{{-4/7}}}.
</pre>