Question 1081988

let Susan’s present age be: {{{x}}}
in {{{7}}} years, Susan will be: {{{x+7}}}
 {{{3}}} years ago she was:{{{x-3}}}

and if {{{x+7}}} will be {{{2}}} times {{{x-3}}, we have

{{{x+7=2(x-3)}}}.........solve for {{{x}}}

{{{x+7=2x-6}}}

{{{6+7=2x-x}}}

{{{13=x}}}

so, Susan’s present age is {{{13}}} 


check:
present age is {{{13}}}

in {{{7}}} years, Susan will be: {{{20}}}
{{{3}}} years ago she was:{{{10}}}

{{{20=2(10)}}}

{{{20=20}}}.........which confirms our result