Question 1081923
{{{sqrt(6x^2+5x)=2}}}
{{{6x^2+5x=4}}}
{{{6x^2+5x-4=0}}}
{{{(2x-1)(3x+4)=0}}}
So,
{{{2x-1=0}}}
{{{2x=1}}}
{{{x=1/2}}}
and
{{{3x+4=0}}}
{{{3x=-4}}}
{{{x=-4/3}}}