Question 1081917
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Since (x-1) is a factor of  p(x) = {{{k^2*x^2 - 2kx -3}}},  you have 

p(1) = 0,   or   {{{k^2*1^2 - 2k*1 -3}}} = 0,   which gives you an equation

{{{k^2 - 2k - 3}}} = 0.

It is equivalent to

(k-3)*(k+1) = 0.

The roots are k= 3  and/or  k= -1.


<U>Answer</U>.  k= 3  or   k = -1.
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