Question 13556
Let r=regular
s=student
m=member
There are 3 different equations in this problem.
r+m+s=750 (equation 1)
r+0m-s=-20 (equation 2)
10r+7m+5s=5400 (equation 3)
First take the first two equations, use the elimination method to eliminate one variable. Eliminate r
-10r-10m-10s=-7500
10r+7m+5s=5400 (equation 4)
Now take the first and third equations and use the same method and eliminate the same variable
-r-m-s=-750
r+0m-s=-20
-m-2s=-770 (equation 5)
Take equation 4 and equation 5, use the same method, and eliminate one of the remaining variables
3m+6s=2310
-3m-5s=-2100
s=210
plug in the value of s into either equation 4 or 5
-m-2(210)=-770
-m-420=-770
-m=-350
m=350
Now take the m and s values and plug them into one of the 3 original equations
r+350+210=750
r+560=720
r=190
There were 190 regular tickets sold,350 member tickets sold,and 210 student tickets sold