Question 1081707
{{{2sin(2x-pi/6)+1=0}}}
{{{2sin(2x-pi/6)=-1}}}
{{{sin(2x-pi/6)=-1/2}}}
So,
{{{2x-pi/6=(7/6)pi+2pi*k}}} and {{{2x-pi/6=(11/6)pi+2pi*k}}}
{{{2x=(8/6)pi+2pi*k}}} and {{{2x=(12/6)pi+2pi*k}}}
{{{x=(2/3)pi+pi*k}}} and {{{x=pi+pi*k}}}
and
{{{x=(2/3)pi}}}
{{{x=pi}}}
{{{x=(5/3)pi}}}
{{{x=2pi}}}
Adjusting for the range, subtract {{{pi}}} from each answer.
{{{x=-(1/3)pi}}}
{{{x=0}}}
{{{x=(2/3)pi}}}
{{{x=pi}}}
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