Question 1081712

There are initially 12 face cards in the deck.

We are interested in the case that we draw 4 consecutive face cards on a draw of 4 cards.  That means the first one has a probability of 12/52 of being drawn, that would leave 11 face cards among the remaining 51 cards, etc.  Similar logic applies to the remaining draws.
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P(4 face cards drawn) = (12/52)*(11/51)*(10/50)*(9/49) 
which reduces to  (3/13)*(11/51)*(1/5)*(9/49) =  297 / 162435 = {{{ highlight(99/54145)}}}