Question 1081706
{{{A=(matrix(3,3,
1,1,-1,
3,1,-2,
1,-1,-1))}}}
{{{abs(A)=2}}}
.
.

{{{A[x]=(matrix(3,3,
1,1,-1,
3,1,-2,
-1,-1,-1))}}}
{{{abs(A[x])=4}}}
.
.


{{{A[y]=(matrix(3,3,
1,1,-1,
3,3,-2,
1,-1,-1))}}}
{{{abs(A[y])=2}}}
.
.


{{{A[z]=(matrix(3,3,
1,1,1,
3,1,3,
1,-1,-1))}}}
{{{abs(A[z])=4}}}
.
.

So,
{{{x=abs(A[x])/abs(A)=4/2=2}}}
{{{y=abs(A[y])/abs(A)=2/2=1}}}
{{{z=abs(A[z])/abs(A)=4/2=2}}}