Question 1081652


use Pythagorean theorem:
 
{{{c^2=a^2+b^2}}} than {{{a^2=c^2-b^2}}}

if leg {{{b=12}}} and hypotenuse {{{c=13}}} will be:

{{{a^2=13^2-12^2}}}

{{{a^2=169-144}}}

{{{a^2=25}}}

{{{a=sqrt(25)}}}

{{{a=5}}}