Question 1081642
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ y^2\ +\ 4y\ +\ 2]


Complete the square


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ y^2\ +\ 4y\ +\ 4\ -\ 2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ (y\ +\ 2)^2\ -\ 2]


Read the center coordinates directly using the standard form definition of a parabola with a horizontal axis and a vertex at *[tex \LARGE (h,\,k)]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ a(y\ -\ k)\ +\ h]


Rewrite the completed square form


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \left(y\ -\ (-2)\right)^2\ +\ (-2)]


to help keep your signs straight.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  


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