Question 1081541
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<pre>
Let a = "How many metric tons per day furnace A produces",
    b = same for B,
    c = same for C.

Then you have these equations:

a   + b   + c   = 800,     (1)
a/2 + b/2 + c   = 545,     (2)
      b   + c/2 = 410.     (3)

Now multiply eq(2) by 2 (both sides), and then subtract eq(1) from it. You will get

a + b +  c  = 800          (1)
a + b + 2c = 1090          (4)
--------------------subtract      eq(1) from eq(4)

         c = 1090 - 800 = 290.

Having this, find b from (3).

Having b and c, find a from (1).
</pre>

For similar problems, see the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Rate-of-work-word-problems/Joint-work-word-problems-for-3-4-5-participants.lesson>Joint-work problems for 3 participants</A>

in this site.



Also, you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this textbook under the topic "<U>Rate of work and joint work problems</U>" of the section "<U>Word problems</U>".