Question 1081467


{{{SA = 4pi*r^2}}} where {{{r}}} is the radius

the diameter of a sphere with a surface area of {{{SA=81*pi*yd^2}}} is:

{{{4pi*r^2=81*pi*yd^2}}}

{{{r^2=(81*pi*yd^2)/4pi}}}

{{{r^2=(81*cross(pi)*yd^2)/4cross(pi)}}}

{{{r^2=(81yd^2)/4}}}

{{{r=sqrt((81yd^2)/4)}}}

{{{r=sqrt((9^2yd^2))/sqrt(4)}}}

{{{r=9yd/2}}}

{{{r=4.5yd}}}