Question 1081447
{{{(1-3j)+(-2+3j)=(1-2)+(-3+3)j=-1}}}
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{{{(1-3j)/(-2+3j)=c+dj}}}
{{{1-3j=-2c+3cj-2di+3dj^2}}}
{{{1-3j=(-2c-3d)+(3c-2d)j}}}
So,
1.{{{-2c-3d=1}}}
2.{{{3c-2d=-3}}}
Multiply eq. 1 by 3 and eq. 2 by 2 and add,
{{{-6c-9d+6c-4d=3-6}}}
{{{-13d=-3}}}
{{{d=3/13}}}
and
{{{3c-2(3/13)=-3}}}
{{{3c-6/13=-39/13}}}
{{{3c=-39/13+6/13}}}
{{{3c=-33/13}}}
{{{c=-11/13}}}
So,
{{{(1-3j)/(-2+3j)=-(11/13)+(3/13)j}}}