Question 1081184
*[illustration A2.png].
.
.
{{{A[1]=x^2}}}
{{{A[2]=y^2}}}
{{{A[1]+A[2]=5200}}}
1.{{{x^2+y^2=5200}}}
For the fence,
{{{3y+(y-x)+3x=320}}}
{{{x+2y=160}}}
2.{{{x=160-2y}}}
Substituting into 1,
{{{(160-2y)^2+y^2=5200}}}
{{{25600-640y+4y^2+y^2-5200=0}}}
{{{5y^2-640y+20800=0}}}
{{{y^2-128y+4080=0}}}
{{{(y-60)(y-68)=0}}}
Two solutions,
{{{y-60=0}}}
{{{y=60}}}
Then,
{{{x=160-2(60)}}}
{{{x=160-120}}}
{{{x=40}}}
and
{{{y-68=0}}}
{{{y=68}}}
Then,
{{{x=160-2(68)}}}
{{{x=160-136}}}
{{{x=24}}}