Question 95472
3y/2+y/6=10/3  solve the linear equation?

L.C.D of 2, 6 , 3 is 6 

Multiply the equation by 6 

3y/2*6+y/6*6=10/3*6

Multiplying by the L.C.D  will remove the fraction



3y *3 + y = 20

9y +y = 20

10y = 20 

10y/10 = 20/10

y = 2

check 
consider the equation and pluggin the value of y in it

3y/2+y/6=10/3 

3(2)/2 +2/6 = 10/3

6/2 +2/6 = 10/3

3 +1/3 = 10/3

(3*3 +1)/3 = 10/3 

(9+1)/3 = 10/3

10/3 = 10/3

LHS = RHS

Hence y = 2 is the solution