Question 1081364
Find the 3rd term in the expansion of the binomial. Thanks.
(x - 2y)12
A.) 264x¹⁰y²
B.) 1760x⁹y³
C.) -264x¹⁰y²
D.) -1760x⁹y³
<pre>{{{(x - 2y)^12}}}
To find a SPECIFIC TERM of a binomial expansion, we use the formula: {{{(a + b)^n = "" [n]C[r - 1](a)^(n - (r - 1))(b)^(r - 1)}}}, where: 
                                                                      r = 3
                                                                      n = 12
                                                                      a = x
                                                                      b = - 2y

We then get: 3rd term of {{{(x - 2y)^12 = "" [12]C[3 - 1](x)^(12 - (3 - 1))(- 2y)^(3 - 1)}}} =====> {{{""[12]C[2](x)^10(- 2y)^2}}} ======> {{{highlight_green(matrix(1,4, 66x^10 * 4y^2, "=", 264x^10y^2, highlight(matrix(1,2, "(CHOICE", "A.)"))))}}}