Question 1081332

the surface area of a {{{rectangle}}} with {{{10ft}}},{{{5ft}}},{{{4ft}}}

first, a {{{rectangle}}} is two-dimensional, has the length and width

you are given three dimensions: length {{{10ft}}}, width {{{5ft}}}, and height {{{4ft}}}

so, you have a three-dimensional object which is a {{{prism}}} with {{{rectangular}}} bases; the term "three-dimensional" is in reference to those three measurements

if {{{a=10ft}}},{{{b=5ft}}},{{{h=4ft}}}, the surface area will be:

{{{SA = 2(ab) + 2(ah) + 2(bh )}}}

{{{SA = 2(10ft*5ft) + 2(10ft*4ft) + 2(5ft*4ft )}}}

{{{SA = 2(50ft^2) + 2(40ft^2) + 2(20ft^2 )}}}

{{{SA = 100ft^2 + 80ft^2 + 40ft^2 }}}

{{{SA = 220ft^2 }}}